- QUESTION
A certain amount of money at compound interest grows to 66,550 in 3 years and 73,205 in 4 years. The rate percent per annum is:
A)10%
B)9%
C)5%
D)11%
Explanation
(A)
=Amount will become in 4 years = 73205
Amount will become in 3 years = 66550
Interest = 73205-66550 = 6655
. Rate of interest = 6655/66550 * 100 = 10%
16(A)
=Amount will become in 4 years = 73205
Amount will become in 3 years = 66550
Interest = 73205-66550 = 6655
. Rate of interest = 6655/66550 * 100 = 10%
Question 2.
Ramesh invests 1,200 at 5% simple interest. How much additional money must he invest at 8% simple interest so that his total annual income will be equal to 6% of his total investment during this year?
A)500
B)600
C)1,200
D)1,500
Explanation
(B)
=Let’s break down the problem:
1. Ramesh invests $1200 at 5% simple interest.
2. He wants his total annual income to be equal to 6% of his total investment.
Let’s denote the additional amount he needs to invest at 8% as \(x\).
So, for the $1200 invested at 5%, his income would be \(1200 \times 0.05 = $60\).
For the additional amount invested at 8%, his income would be \(x \times 0.08\).
To meet his target of 6% annual income, the total income should be 6% of the total investment, which is \(0.06 \times (1200 + x)\).
Therefore, we can set up the equation:
\[60 + 0.08x = 0.06 \times (1200 + x)\]
Now, solve for \(x\):
\[60 + 0.08x = 72 + 0.06x\]
\[0.08x – 0.06x = 72 – 60\]
\[0.02x = 12\]
\[x = \frac{12}{0.02}\]
\[x = 600\]
So, Ramesh must invest an additional $600 at 8% simple interest.
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