Q1. What is the 95th term of the following letter series?
A, A, B, B, B, B,C, C,C, C,C, C, D, D, D, D, D, D, D, D, E, …
A H
B I
C J
D K
EXPLANATION
.C
A – 2 terms
B – 4 terms
C – 6 terms
..
2 + 4 + 6 + ….. 2n terms => this sum should be greater than or equal to 95.
2 (1 + 2 + 3 + … + n) ≥ 95
n (n + 1) ≥ 95
If n = 9, we get only 90 terms.
95th term occurs when n = 10, i.e. J.
The answer is option C.
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