Q1. Identify odd group of letters:
CE, IK, SV, FH, UW
A sv
B IK
C uw
D FH
EXPLANATION
A
In the following group of letters, CE has one latter gap between them ( C_E). IK has one letter gap (I_K), SV has
(S_ _ V) two letter gap, FH has one letter gap between them (F_H), and UW has one letter gap (U_W).
Hence, all the groups of letters have one letter gap between the first letter and the second letter, except SV.
Hence, SV is the odd one out.
The correct option is A.
Q2. Find the missing term :
A UD2
B VE1
C V4C
D DD3
EXPLANATION
B
There is no number with the first alphabet in the first and the third terms, which implies the fifth term will be
V(alphabetically, the order decreases starting with z). The second letter in each term increases starting with A.
Hence the second letter in the fifth term is E. (VE)
Hence option B is the correct answer.
Leave a Reply